Iodine is sparingly soluble in pure water. However, it does `dissolve’ in solutions containing excess iodide ion because of the following reaction:

I(aq) + I2(aq)= I3(aq) K = 710

[I3^-] to [I2].

5.00×10-2 mol of I2 is added to 1.00 L of 5.00×10-1 M KI solution.

The solution above is diluted to 12.00 L.

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